Postico 1 5 1000

1. Postico 1 5 1000 Mg
2. Postico 1 5 1000 Piece
3. Postico 1 5 1000 Per

Dilution Formula : C1V1 = C2V2

This equation applies to all dilution problems.

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Example : What volume of 6.00 ppm solution must be used to give 4.00 liters of a 0.100 ppm solution?

C1 = 6.00 ppm
V1 = unknown
C2 = 0.100 ppm
V2 = 4 liters = 4000 mls

V1 = (C2 x V2) / C1

= (0.100 X 4000) / 6.00
= 400 / 6.00 = 66.7 mls.

This means that 66.7 mls of the 6.00ppm solution diluted to a final volume of 4 liters will give a concentration of 0.100 ppm.

The Formula below can be used to calculate the the V1 component only.

req is the value you want.

req ppm x req vol
-------------------------- = no of mls for req vol
stock
Example : Make up 50 mls vol of 25 ppm from 100 ppm standard.
25 x 50 / 100 = 12.5 mls. i.e. 12.5 mls of 100 ppm in 50 ml volume will give a 25 ppm solution

Serial dilutions

Making up 10^-1 M to 10^-5 M solutions from a 1M stock solution.
Pipette 10 ml of the 1M stock into a 100 ml volumetric flask and make up to the mark to give a 10^-1 M soln.
Now, pipette 10 ml of this 10^-1 M soln. into another 100 ml flask and make up to the mark to give a 10^-2 M soln.
Pipette again, 10 ml of this 10^-2 M soln. into yet another 100 ml flask and make up to mark to give a 10^-3 M soln.
Pipette a 10 ml of this 10^-3 M soln. into another 100 ml flask and make up to mark to give a 10^-4 M soln.
And from this 10^-4 M soln. pipette 10 ml into a 100 ml flask and make up to mark to give a final 10

^-5 M solution.

Molarity to ppm

Convert molar concentration to grams per liter (Molarity x Atomic mass of solute), then convert to milligrams per liter (ppm) by multiplying by 1000.
e.g. What is the ppm concentration of calcium ion in 0.01M CaCO

Postico 1 5 1000 Mg

₃?

Postico 1 5 1000 Piece

Postico 1 5 1000 Per

Molarity(M) x Atomic mass(At Wt) = grams per liter(g/l)
Atomic Mass (Wt.) of Ca = 40
0.01M x 40 =0.40 g/l
0.40g/l x 1000 = 400 mg/l = 400ppm
Note:
The FW of an ion species is equal to its concentration in ppm at 10^-3M. Fluoride has a FW of 19, hence a 10^-3M concentration is equal to 19ppm, 1M is equal to 19,000 ppm and 1ppm is equal to 5.2 x 10^-5M.
Go here for

^-5 M solution.

Molarity to ppm

Convert molar concentration to grams per liter (Molarity x Atomic mass of solute), then convert to milligrams per liter (ppm) by multiplying by 1000.
e.g. What is the ppm concentration of calcium ion in 0.01M CaCO

Postico 1 5 1000 Mg

₃?

Postico 1 5 1000 Piece

Postico 1 5 1000 Per

Molarity(M) x Atomic mass(At Wt) = grams per liter(g/l)
Atomic Mass (Wt.) of Ca = 40
0.01M x 40 =0.40 g/l
0.40g/l x 1000 = 400 mg/l = 400ppm
Note:
The FW of an ion species is equal to its concentration in ppm at 10^-3M. Fluoride has a FW of 19, hence a 10^-3M concentration is equal to 19ppm, 1M is equal to 19,000 ppm and 1ppm is equal to 5.2 x 10^-5M.
Go here for

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